Solve x² + 7x + 12 = 0
Solve the quadratic equation x² + 7x + 12 = 0 using the quadratic formula.
A quadratic equation has the form: ax² + bx + c = 0
From the given equation:
• a = 1 (coefficient of x²)
• b = 7 (coefficient of x)
• c = 12 (constant term)
Standard form: x² + 7x + 12 = 0
The discriminant determines the nature of the roots.
D = b² - 4ac
D = (7)² - 4(1)(12)
Since D = 1 > 0 and √D = 1 (perfect square),
the equation has two distinct RATIONAL roots.
For x² + 7x + 12 = 0, we need two numbers that:
• Multiply to give c = 12
• Add to give b = 7
The numbers are: 3 and 4
Check: 3 × 4 = 12 ✓
Check: 3 + 4 = 7 ✓
x² + 7x + 12 = (x + 3)(x + 4)
Setting each factor equal to zero:
(x + 3) = 0 → x = -3
(x + 4) = 0 → x = -4
Substitute each solution back into the original equation:
For x = -3:
1(-3)² + 7(-3) + 12
= 0 ✓
For x = -4:
1(-4)² + 7(-4) + 12
= 0 ✓
x = -4 or x = -3